-4x=5x+26-2x^2

Solution for -4x=5x+26-2x^2 equation:

-4x=5x+26-2x^2

We move all terms to the left:

-4x-(5x+26-2x^2)=0

We get rid of parentheses

2x^2-5x-4x-26=0

We add all the numbers together, and all the variables

2x^2-9x-26=0

a = 2; b = -9; c = -26;
Δ = b2-4ac
Δ = -92-4·2·(-26)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-17}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+17}{2*2}=\frac{26}{4}
=6+1/2
$